Pages: 1234[5]67...9495969798
14 Feb 2016 08:03 GMT

Here is a last example, that there is something wrong with the point-system in Rating 5. Player A: Places: 5 and 5 - av. Place=5 - av. Points=0,2 -- Player B: Places 1 and 99 - av. Place=50 - av. Points=0,505. Which player had a better performance?
13 Feb 2016 21:54 GMT

My average place is about 3,8 and that's not the inversion of my average points.
13 Feb 2016 20:03 GMT

Sorry, but the average place is not the inverted average points: Here are some easy eaxamples - 2 Games, Places 1 and 9 - average place: 5 - average points: 0,555 --- Places 1 and 99 - average place: 50 - average points: 0,505. The av. places difference is 45 and the av. points diff. is 0,05!!!
13 Feb 2016 18:22 GMT

Arnold: My point - if I have one - is that displaying both would be redundant. Either can be used to compare player's "efficiency" assuming that both are striving to find the shortest solution. I suspect some - perhaps many - are content finding any solution. They play a different game, so comparison is meaningless. Realistically, the one thing shown by all these tables is that if your username is on these lists, you are hopelessly addicted to the pointless pursuit of pushing little, digital boxes around a phantom maze and you probably should get up and go outside more... I think I will... after I finish *one* more level.
13 Feb 2016 15:20 GMT

MnLsDad, you're right, value of last column is inversion of average place, in my case for example: 1/2.5 = 0.4 (cause 1/0.4 = 2.5). I agree with utimm however that average place 2.5 is a more concrete and comprehensible value than its inversion 0.4.
13 Feb 2016 13:32 GMT

Utimm & Arnold: Re: Table 5. Realize how the 'points' are awarded 1/1 for 1st, 1/2 for 2nd, 1/3 for 3rd. So the average is showing exactly what you are asking for, just inverted. MaxKlaxx .99 almost all 1st place. JotaCartas .5 average = 2nd place. Dijana .76 approx 1.5 place. MicMac .34 approx 3rd place. Hugo .25 = 4th place. Rose .20 = 5th place... The fraction is the finish. Arnold .4 = average 2.5 place. Utimm .56 = ave 1.79 place.
12 Feb 2016 11:01 GMT

yes, it is possible
12 Feb 2016 08:45 GMT

To Arnold: It must be possible - to get all the points you must have first all the places. Also it is possible to leave the average points column and add a extra column with the average places.
12 Feb 2016 00:29 GMT

admin1, is it possible (computable) to implement the idea of utimm and to make the last column of table 5 'Average place per level'?
09 Feb 2016 15:25 GMT

To Arnold: Yes - that was my idea.
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